यदि \(U={x:x\in \mathbb{Z},-8\le x\le 8}\) और \(A={x:x^2-4x\le 0}\), तो (A') क्या है?

If \(U={x:x\in \mathbb{Z},-8\le x\le 8}\) and \(A={x:x^2-4x\le 0}\), what is (A')?

Explanation opens after your attempt
Correct Answer

A. ({-8,-7,-6,-5,-4,-3,-2,-1,5,6,7,8})

Step 1

Concept

\(x^2-4x\le 0\Rightarrow 0\le x\le 4\), so \(A=\{0,1,2,3,4\}\). The remaining integers of (U) form (A').

Step 2

Why this answer is correct

The correct answer is A. ({-8,-7,-6,-5,-4,-3,-2,-1,5,6,7,8}). \(x^2-4x\le 0\Rightarrow 0\le x\le 4\), so \(A=\{0,1,2,3,4\}\). The remaining integers of (U) form (A').

Step 3

Exam Tip

\(x^2-4x\le 0\Rightarrow 0\le x\le 4\), इसलिए \(A=\{0,1,2,3,4\}\)। (U) के बाकी पूर्णांक (A') बनाते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x\in \mathbb{Z},-8\le x\le 8}\) और \(A={x:x^2-4x\le 0}\), तो (A') क्या है? / If \(U={x:x\in \mathbb{Z},-8\le x\le 8}\) and \(A={x:x^2-4x\le 0}\), what is (A')?

Correct Answer: A. ({-8,-7,-6,-5,-4,-3,-2,-1,5,6,7,8}). Explanation: \(x^2-4x\le 0\Rightarrow 0\le x\le 4\), इसलिए \(A=\{0,1,2,3,4\}\)। (U) के बाकी पूर्णांक (A') बनाते हैं। / \(x^2-4x\le 0\Rightarrow 0\le x\le 4\), so \(A=\{0,1,2,3,4\}\). The remaining integers of (U) form (A').

Which concept should I revise for this Mathematics MCQ?

\(x^2-4x\le 0\Rightarrow 0\le x\le 4\), so \(A=\{0,1,2,3,4\}\). The remaining integers of (U) form (A').

What exam hint can help solve this Mathematics question?

\(x^2-4x\le 0\Rightarrow 0\le x\le 4\), इसलिए \(A=\{0,1,2,3,4\}\)। (U) के बाकी पूर्णांक (A') बनाते हैं।