\(यदि (U={x:x\in\mathbb{N},1\le x\le 20}) और (A={x:x\) अभाज्य संख्या है\(}) है, तो (A^c) में कितने तत्व होंगे\)?

\(If (U={x:x\in\mathbb{N},1\le x\le 20}) and (A={x:x\) is a prime number\(}), how many elements are in (A^c)\)?

Explanation opens after your attempt
Correct Answer

A. (12)

Step 1

Concept

There are (8) primes from (1) to (20), so (n\(A^c\)=20-8=12). Do not treat (1) as prime.

Step 2

Why this answer is correct

The correct answer is A. (12). There are (8) primes from (1) to (20), so (n\(A^c\)=20-8=12). Do not treat (1) as prime.

Step 3

Exam Tip

(1) से (20) तक (8) अभाज्य संख्याएं हैं, इसलिए (n\(A^c\)=20-8=12)। (1) को अभाज्य न मानें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(यदि (U={x:x\in\mathbb{N},1\le x\le 20}) और (A={x:x\) अभाज्य संख्या है}) है, तो \(A^c\) में कितने तत्व होंगे? \(/ If (U={x:x\in\mathbb{N},1\le x\le 20}) and (A={x:x\) is a prime number\(}), how many elements are in (A^c)\)?

Correct Answer: A. (12). Explanation: (1) से (20) तक (8) अभाज्य संख्याएं हैं, इसलिए (n\(A^c\)=20-8=12)। (1) को अभाज्य न मानें। / There are (8) primes from (1) to (20), so (n\(A^c\)=20-8=12). Do not treat (1) as prime.

Which concept should I revise for this Mathematics MCQ?

There are (8) primes from (1) to (20), so (n\(A^c\)=20-8=12). Do not treat (1) as prime.

What exam hint can help solve this Mathematics question?

(1) से (20) तक (8) अभाज्य संख्याएं हैं, इसलिए (n\(A^c\)=20-8=12)। (1) को अभाज्य न मानें।