यदि \(U=\mathbb{R}\) और \(A={x:x\in\mathbb{R},x^2+2x-8<0}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x\in\mathbb{R},x^2+2x-8<0}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-4]\cup[2,\infty\))
Concept
The solution of \(x^2+2x-8<0\) is (-4<x<2). Hence the complement is (\(-\infty,-4]\cup[2,\infty\)).
Why this answer is correct
The correct answer is A. (\(-\infty,-4]\cup[2,\infty\)). The solution of \(x^2+2x-8<0\) is (-4<x<2). Hence the complement is (\(-\infty,-4]\cup[2,\infty\)).
Exam Tip
असमानता \(x^2+2x-8<0\) का हल (-4<x<2) है। इसलिए पूरक में (\(-\infty,-4]\cup[2,\infty\)) आएगा।
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