यदि \(U=\mathbb{R}\) और \(A={x:x \in \mathbb{R}, -1<x\le 6}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x \in \mathbb{R}, -1<x\le 6}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. ((-\infty,-1] \cup \(6,\infty\))
Concept
The point (-1) is not in (A), so it is included in the complement, while (6) is in (A), so it is excluded.
Why this answer is correct
The correct answer is A. ((-\infty,-1] \cup \(6,\infty\)). The point (-1) is not in (A), so it is included in the complement, while (6) is in (A), so it is excluded.
Exam Tip
(-1) (A) में नहीं है इसलिए पूरक में शामिल है, जबकि (6) (A) में है इसलिए पूरक में नहीं है।
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