यदि \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},|x+1|\ge 4}\), तो (A') क्या है?

If \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},|x+1|\ge 4}\), what is (A')?

Explanation opens after your attempt
Correct Answer

A. ((-5,3))

Step 1

Concept

The solution of \(|x+1|\ge 4\) is \(x\le -5\) or \(x\ge 3\). Hence its complement is (-5<x<3).

Step 2

Why this answer is correct

The correct answer is A. ((-5,3)). The solution of \(|x+1|\ge 4\) is \(x\le -5\) or \(x\ge 3\). Hence its complement is (-5<x<3).

Step 3

Exam Tip

\(|x+1|\ge 4\) का हल \(x\le -5\) या \(x\ge 3\) है। इसलिए इसका पूरक (-5<x<3) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},|x+1|\ge 4}\), तो (A') क्या है? / If \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},|x+1|\ge 4}\), what is (A')?

Correct Answer: A. ((-5,3)). Explanation: \(|x+1|\ge 4\) का हल \(x\le -5\) या \(x\ge 3\) है। इसलिए इसका पूरक (-5<x<3) है। / The solution of \(|x+1|\ge 4\) is \(x\le -5\) or \(x\ge 3\). Hence its complement is (-5<x<3).

Which concept should I revise for this Mathematics MCQ?

The solution of \(|x+1|\ge 4\) is \(x\le -5\) or \(x\ge 3\). Hence its complement is (-5<x<3).

What exam hint can help solve this Mathematics question?

\(|x+1|\ge 4\) का हल \(x\le -5\) या \(x\ge 3\) है। इसलिए इसका पूरक (-5<x<3) है।