यदि \(U=\mathbb{R}\), \(A={x:-2<x\le 4}\) और \(B={x:1\le x<7}\), तो \(A'\cup B'\) क्या है?

If \(U=\mathbb{R}\), \(A={x:-2<x\le 4}\) and \(B={x:1\le x<7}\), what is \(A'\cup B'\)?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,1\)\cup\(4,\infty\))

Step 1

Concept

(A'\cup B'=\(A\cap B\)'), and \(A\cap B=[1,4]\). Therefore the complement is (\(-\infty,1\)\cup\(4,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,1\)\cup\(4,\infty\)). (A'\cup B'=\(A\cap B\)'), and \(A\cap B=[1,4]\). Therefore the complement is (\(-\infty,1\)\cup\(4,\infty\)).

Step 3

Exam Tip

(A'\cup B'=\(A\cap B\)') और \(A\cap B=[1,4]\) है। इसलिए पूरक (\(-\infty,1\)\cup\(4,\infty\)) होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\mathbb{R}\), \(A={x:-2<x\le 4}\) और \(B={x:1\le x<7}\), तो \(A'\cup B'\) क्या है? / If \(U=\mathbb{R}\), \(A={x:-2<x\le 4}\) and \(B={x:1\le x<7}\), what is \(A'\cup B'\)?

Correct Answer: A. (\(-\infty,1\)\cup\(4,\infty\)). Explanation: (A'\cup B'=\(A\cap B\)') और \(A\cap B=[1,4]\) है। इसलिए पूरक (\(-\infty,1\)\cup\(4,\infty\)) होगा। / (A'\cup B'=\(A\cap B\)'), and \(A\cap B=[1,4]\). Therefore the complement is (\(-\infty,1\)\cup\(4,\infty\)).

Which concept should I revise for this Mathematics MCQ?

(A'\cup B'=\(A\cap B\)'), and \(A\cap B=[1,4]\). Therefore the complement is (\(-\infty,1\)\cup\(4,\infty\)).

What exam hint can help solve this Mathematics question?

(A'\cup B'=\(A\cap B\)') और \(A\cap B=[1,4]\) है। इसलिए पूरक (\(-\infty,1\)\cup\(4,\infty\)) होगा।