यदि \(U=\mathbb{R}\), \(A={x:-1\le x<5}\) और \(B={x:2<x\le 8}\), तो \(A'\cup B'\) क्या है?
If \(U=\mathbb{R}\), \(A={x:-1\le x<5}\) and \(B={x:2<x\le 8}\), what is \(A'\cup B'\)?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,2]\cup[5,\infty\))
Concept
(A'\cup B'=\(A\cap B\)'), and \(A\cap B=(2,5)\). Therefore the complement is (\(-\infty,2]\cup[5,\infty\)).
Why this answer is correct
The correct answer is A. (\(-\infty,2]\cup[5,\infty\)). (A'\cup B'=\(A\cap B\)'), and \(A\cap B=(2,5)\). Therefore the complement is (\(-\infty,2]\cup[5,\infty\)).
Exam Tip
(A'\cup B'=\(A\cap B\)') और \(A\cap B=(2,5)\) है। इसलिए पूरक (\(-\infty,2]\cup[5,\infty\)) होगा।
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