यदि \(U=\mathbb{R}\), (A=(-2,6]) और (B=[0,9)), तो \(A'\cup B'\) क्या है?

If \(U=\mathbb{R}\), (A=(-2,6]), and (B=[0,9)), what is \(A'\cup B'\)?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,0\)\cup\(6,\infty\))

Step 1

Concept

By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,0\)\cup\(6,\infty\)). By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).

Step 3

Exam Tip

डी मॉर्गन से (A'\cup B'=\(A\cap B\)') है। \(A\cap B=[0,6]\), इसलिए पूरक (\(-\infty,0\)\cup\(6,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\mathbb{R}\), (A=(-2,6]) और (B=[0,9)), तो \(A'\cup B'\) क्या है? / If \(U=\mathbb{R}\), (A=(-2,6]), and (B=[0,9)), what is \(A'\cup B'\)?

Correct Answer: A. (\(-\infty,0\)\cup\(6,\infty\)). Explanation: डी मॉर्गन से (A'\cup B'=\(A\cap B\)') है। \(A\cap B=[0,6]\), इसलिए पूरक (\(-\infty,0\)\cup\(6,\infty\)) है। / By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).

Which concept should I revise for this Mathematics MCQ?

By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).

What exam hint can help solve this Mathematics question?

डी मॉर्गन से (A'\cup B'=\(A\cap B\)') है। \(A\cap B=[0,6]\), इसलिए पूरक (\(-\infty,0\)\cup\(6,\infty\)) है।