यदि (|U|=64), \(|A\cap B|=18\), \(|A'\cap B|=12\) और \(|A\cap B'|=20\), तो \(|A'\cap B'|\) कितना है?
If (|U|=64), \(|A\cap B|=18\), \(|A'\cap B|=12\), and \(|A\cap B'|=20\), what is \(|A'\cap B'|\)?
Explanation opens after your attempt
B. (14)
Concept
The four disjoint regions add up to (|U|). Therefore \(|A'\cap B'|=64-18-12-20=14\).
Why this answer is correct
The correct answer is B. (14). The four disjoint regions add up to (|U|). Therefore \(|A'\cap B'|=64-18-12-20=14\).
Exam Tip
चार असंयुक्त भागों का योग (|U|) होता है। इसलिए \(|A'\cap B'|=64-18-12-20=14\)।
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