\(यदि (U={1,2,\ldots,96}), (A={x:x\) 6 से विभाज्य है\(}) और (B={x:x\) 8 से विभाज्य है\(}), तो (|(A\cup B)'|) कितना है\)?
\(If (U={1,2,\ldots,96}), (A={x:x\) is divisible by \(6}) and (B={x:x\) is divisible by \(8}), what is (|(A\cup B)'|)\)?
Explanation opens after your attempt
C. (72)
Concept
(A) has (16) elements, (B) has (12), and \(A\cap B\) has (4) multiples of (24), so \(|A\cup B|=24\). Hence (|\(A\cup B\)'|=96-24=72).
Why this answer is correct
The correct answer is C. (72). (A) has (16) elements, (B) has (12), and \(A\cap B\) has (4) multiples of (24), so \(|A\cup B|=24\). Hence (|\(A\cup B\)'|=96-24=72).
Exam Tip
(A) में (16), (B) में (12) और \(A\cap B\) में (24) के (4) गुणज हैं, इसलिए \(|A\cup B|=24\)। अतः (|\(A\cup B\)'|=96-24=72)।
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