\(यदि (U={1,2,\ldots,36}), (A={x:x\) 2 से विभाज्य है\(}), (B={x:x\) 3 से विभाज्य है\(}), (C={x:x\) 6 से विभाज्य है\(}), तो (|(A\cup B\cup C)'|) कितना है\)?
\(If (U={1,2,\ldots,36}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}), (C={x:x\) is divisible by \(6}), what is (|(A\cup B\cup C)'|)\)?
Explanation opens after your attempt
Correct Answer
C. (12)
Concept
Since \(C\subseteq A\) and \(C\subseteq B\), \(A\cup B\cup C=A\cup B\). \(|A\cup B|=18+12-6=24\), so the complement is (36-24=12).
Why this answer is correct
The correct answer is C. (12). Since \(C\subseteq A\) and \(C\subseteq B\), \(A\cup B\cup C=A\cup B\). \(|A\cup B|=18+12-6=24\), so the complement is (36-24=12).
Exam Tip
क्योंकि \(C\subseteq A\) और \(C\subseteq B\), इसलिए \(A\cup B\cup C=A\cup B\)। \(|A\cup B|=18+12-6=24\), अतः पूरक (36-24=12) है।
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