\(यदि (U={1,2,\ldots,32}), (A={x:x\) 4 का गुणज है\(}) और (B={x:x\) 16 का गुणज है\(}), तो (A'\cup B) में कितने अवयव हैं\)?
\(If (U={1,2,\ldots,32}), (A={x:x\) is a multiple of \(4}) and (B={x:x\) is a multiple of \(16}), how many elements are in (A'\cup B)\)?
Explanation opens after your attempt
Correct Answer
C. (26)
Concept
(A') has (32-8=24) elements and \(B\subseteq A\), so \(A'\cap B=\varnothing\). (B) has (2) elements, hence the total is (26).
Why this answer is correct
The correct answer is C. (26). (A') has (32-8=24) elements and \(B\subseteq A\), so \(A'\cap B=\varnothing\). (B) has (2) elements, hence the total is (26).
Exam Tip
(A') में (32-8=24) अवयव हैं और \(B\subseteq A\), इसलिए \(A'\cap B=\varnothing\)। (B) में (2) अवयव हैं, अतः कुल (26) है।
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