\(यदि (U={1,2,\ldots,24}), (A={x:x\in U,x\) विषम है\(}) और (B={x:x\in U,x\) अभाज्य है\(}), तो (A\cap B') क्या है\)?
\(If (U={1,2,\ldots,24}), (A={x:x\in U,x\) is odd\(}), and (B={x:x\in U,x\) is prime\(}), what is (A\cap B')\)?
Explanation opens after your attempt
Correct Answer
A. ({1,9,15,21,23})
Concept
\(A\cap B'\) contains odd numbers that are not prime. Since (23) is prime, the correct set is ({1,9,15,21}).
Why this answer is correct
The correct answer is A. ({1,9,15,21,23}). \(A\cap B'\) contains odd numbers that are not prime. Since (23) is prime, the correct set is ({1,9,15,21}).
Exam Tip
\(A\cap B'\) में विषम लेकिन अभाज्य नहीं संख्याएं आती हैं। (23) अभाज्य है, इसलिए सही समुच्चय ({1,9,15,21}) होना चाहिए।
Login to save your score, XP, coins and progress.