\(यदि (U={1,2,\ldots,20}), (A={x:x\in U,\ x\) अभाज्य है\(}) और (B={x:x\in U,\ x\) विषम है\(}), तो (A\setminus B) क्या है\)?
\(If (U={1,2,\ldots,20}), (A={x:x\in U,\ x\) is prime\(}) and (B={x:x\in U,\ x\) is odd\(}), what is (A\setminus B)\)?
Explanation opens after your attempt
Correct Answer
A. ({2})
Concept
Among primes, only (2) is even, so \(A\setminus B={2}\). Do not treat (1) as prime.
Why this answer is correct
The correct answer is A. ({2}). Among primes, only (2) is even, so \(A\setminus B={2}\). Do not treat (1) as prime.
Exam Tip
अभाज्य संख्याओं में केवल (2) सम है, इसलिए \(A\setminus B={2}\)। (1) को अभाज्य न मानें।
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