\(यदि (U={1,2,\ldots,20}), (A={x:x \in U,x\) सम है\(}) और (B={x:x \in U,x\) अभाज्य है\(}), तो (A'\cap B) क्या है\)?

\(If (U={1,2,\ldots,20}), (A={x:x \in U,x\) is even\(}), and (B={x:x \in U,x\) is prime\(}), what is (A'\cap B)\)?

Explanation opens after your attempt
Correct Answer

A. ({3,5,7,11,13,17,19})

Step 1

Concept

(A') is the set of odd numbers and (B) is the set of primes. Thus \(A'\cap B\) contains all odd primes except (2).

Step 2

Why this answer is correct

The correct answer is A. ({3,5,7,11,13,17,19}). (A') is the set of odd numbers and (B) is the set of primes. Thus \(A'\cap B\) contains all odd primes except (2).

Step 3

Exam Tip

(A') विषम संख्याओं का समुच्चय है और (B) अभाज्य संख्याओं का। इसलिए \(A'\cap B\) में (2) को छोड़कर सभी विषम अभाज्य आएंगे।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={1,2,\ldots,20}), (A={x:x \in U,x\) सम है\(}) और (B={x:x \in U,x\) अभाज्य है}), तो \(A'\cap B\) क्या है? \(/ If (U={1,2,\ldots,20}), (A={x:x \in U,x\) is even\(}), and (B={x:x \in U,x\) is prime\(}), what is (A'\cap B)\)?

Correct Answer: A. ({3,5,7,11,13,17,19}). Explanation: (A') विषम संख्याओं का समुच्चय है और (B) अभाज्य संख्याओं का। इसलिए \(A'\cap B\) में (2) को छोड़कर सभी विषम अभाज्य आएंगे। / (A') is the set of odd numbers and (B) is the set of primes. Thus \(A'\cap B\) contains all odd primes except (2).

Which concept should I revise for this Mathematics MCQ?

(A') is the set of odd numbers and (B) is the set of primes. Thus \(A'\cap B\) contains all odd primes except (2).

What exam hint can help solve this Mathematics question?

(A') विषम संख्याओं का समुच्चय है और (B) अभाज्य संख्याओं का। इसलिए \(A'\cap B\) में (2) को छोड़कर सभी विषम अभाज्य आएंगे।