\(यदि (U={1,2,\ldots,20}), (A={x:x\in U,\ x\) सम है\(}) और (B={x:x\in U,\ x\) 3 से विभाज्य है\(}) है, तो (n((A\cup B)')) कितना है\)?
\(If (U={1,2,\ldots,20}), (A={x:x\in U,\ x\) is even\(}), and (B={x:x\in U,\ x\) is divisible by \(3}), then what is (n((A\cup B)'))\)?
Explanation opens after your attempt
Correct Answer
A. (7)
Concept
(n(A)=10), (n(B)=6), (n\(A\cap B\)=3), so (n\(A\cup B\)=13). The complement has (20-13=7) elements.
Why this answer is correct
The correct answer is A. (7). (n(A)=10), (n(B)=6), (n\(A\cap B\)=3), so (n\(A\cup B\)=13). The complement has (20-13=7) elements.
Exam Tip
(n(A)=10), (n(B)=6), (n\(A\cap B\)=3), अतः (n\(A\cup B\)=13)। पूरक में (20-13=7) तत्व हैं।
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