यदि \(U={1,2,\ldots,14}\), \(A=\{2,4,6,8,10,12,14\}\), तो \(A'\times A\) में कितने क्रमित युग्म होंगे?
If \(U={1,2,\ldots,14}\), \(A=\{2,4,6,8,10,12,14\}\), how many ordered pairs are in \(A'\times A\)?
Explanation opens after your attempt
Correct Answer
A. (49)
Concept
(A') has (7) odd elements and (A) has (7) even elements. Hence (n\(A'\times A\)=7\times 7=49).
Why this answer is correct
The correct answer is A. (49). (A') has (7) odd elements and (A) has (7) even elements. Hence (n\(A'\times A\)=7\times 7=49).
Exam Tip
(A') में (7) विषम सदस्य और (A) में (7) सम सदस्य हैं। इसलिए (n\(A'\times A\)=7\times 7=49) है।
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