\(यदि (U={1,2,\ldots,100}), (A={x:x\) पूर्ण वर्ग है}), तो (|A'|) कितना है?

\(If (U={1,2,\ldots,100}), (A={x:x\) is a perfect square}), what is (|A'|)?

Explanation opens after your attempt
Correct Answer

B. (90)

Step 1

Concept

Perfect squares up to (100) are from \(1^2\) to \(10^2\), giving (10) elements. Hence (|A'|=100-10=90).

Step 2

Why this answer is correct

The correct answer is B. (90). Perfect squares up to (100) are from \(1^2\) to \(10^2\), giving (10) elements. Hence (|A'|=100-10=90).

Step 3

Exam Tip

(100) तक पूर्ण वर्ग \(1^2\) से \(10^2\) तक (10) हैं। इसलिए (|A'|=100-10=90)।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={1,2,\ldots,100}), (A={x:x\) पूर्ण वर्ग है}), तो (|A'|) कितना है? \(/ If (U={1,2,\ldots,100}), (A={x:x\) is a perfect square}), what is (|A'|)?

Correct Answer: B. (90). Explanation: (100) तक पूर्ण वर्ग \(1^2\) से \(10^2\) तक (10) हैं। इसलिए (|A'|=100-10=90)। / Perfect squares up to (100) are from \(1^2\) to \(10^2\), giving (10) elements. Hence (|A'|=100-10=90).

Which concept should I revise for this Mathematics MCQ?

Perfect squares up to (100) are from \(1^2\) to \(10^2\), giving (10) elements. Hence (|A'|=100-10=90).

What exam hint can help solve this Mathematics question?

(100) तक पूर्ण वर्ग \(1^2\) से \(10^2\) तक (10) हैं। इसलिए (|A'|=100-10=90)।