यदि छायांकित भाग (x)-अक्ष के ऊपर, (y)-अक्ष के दाईं ओर और (2x+y=10) के नीचे सीमा सहित है, तो असमानताओं का तंत्र कौन-सा है?
If the shaded part is above the (x)-axis, to the right of the (y)-axis, and below (2x+y=10) with boundary, which system of inequalities represents it?
Explanation opens after your attempt
D. \(x\geq 0\), \(y\geq 0\), \(2x+y\leq 10\)
Concept
The axis directions give \(x\geq 0\), \(y\geq 0\), and being below the line gives \(2x+y\leq 10\). Exam tip: Convert words into axis inequalities first.
Why this answer is correct
The correct answer is D. \(x\geq 0\), \(y\geq 0\), \(2x+y\leq 10\). The axis directions give \(x\geq 0\), \(y\geq 0\), and being below the line gives \(2x+y\leq 10\). Exam tip: Convert words into axis inequalities first.
Exam Tip
अक्षों की दिशा से \(x\geq 0\), \(y\geq 0\) और रेखा के नीचे से \(2x+y\leq 10\) मिलता है। परीक्षा सुझाव: शब्दों को पहले अक्षीय असमानताओं में बदलें।
Login to save your score, XP, coins and progress.