यदि (n\(A\cup B\cup C\)=86), (n(A)=38), (n(B)=34), (n(C)=31), (n\(A\cap B\)=12), (n\(B\cap C\)=10), (n\(C\cap A\)=9) है, तो (n\(A\cap B\cap C\)) कितना है?
If (n\(A\cup B\cup C\)=86), (n(A)=38), (n(B)=34), (n(C)=31), (n\(A\cap B\)=12), (n\(B\cap C\)=10), (n\(C\cap A\)=9), then what is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
A. (14)
Concept
Use the formula for three sets: (86=38+34+31-12-10-9+x). This gives (x=14).
Why this answer is correct
The correct answer is A. (14). Use the formula for three sets: (86=38+34+31-12-10-9+x). This gives (x=14).
Exam Tip
तीन समुच्चयों का सूत्र लगाएं: (86=38+34+31-12-10-9+x)। इससे (x=14) मिलता है।
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