यदि (n\(A\cap B\cap C\)=9), केवल \(A\cap B\) में (14), केवल \(B\cap C\) में (11), और केवल \(C\cap A\) में (13) तत्व हैं, तो (n(\(A\cap B\)\cup\(B\cap C\)\cup\(C\cap A\))) कितना है?
If (n\(A\cap B\cap C\)=9), only \(A\cap B\) has (14), only \(B\cap C\) has (11), and only \(C\cap A\) has (13) elements, then what is (n(\(A\cap B\)\cup\(B\cap C\)\cup\(C\cap A\)))?
Explanation opens after your attempt
A. (47)
Concept
Elements in at least two sets are (14+11+13+9=47). In the Venn diagram, count the centre only once.
Why this answer is correct
The correct answer is A. (47). Elements in at least two sets are (14+11+13+9=47). In the Venn diagram, count the centre only once.
Exam Tip
कम से कम दो समुच्चयों में आने वाले तत्व (14+11+13+9=47) हैं। वेन आरेख में केंद्र को एक बार ही गिनें।
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