यदि (n\(A\cap B'\)=18), (n\(A'\cap B\)=22), (n\(A\cap B\)=16), और (n(U)=75) है, तो (n\(A'\cap B'\)) क्या है?
If (n\(A\cap B'\)=18), (n\(A'\cap B\)=22), (n\(A\cap B\)=16), and (n(U)=75), what is (n\(A'\cap B'\))?
Explanation opens after your attempt
Correct Answer
A. (19)
Concept
The union is (18+22+16=56), so outside both is (75-56=19). The four regions together make (U).
Why this answer is correct
The correct answer is A. (19). The union is (18+22+16=56), so outside both is (75-56=19). The four regions together make (U).
Exam Tip
संघ (18+22+16=56) है, इसलिए दोनों के बाहर (75-56=19)। चार क्षेत्रों का कुल योग (U) होता है।
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