यदि (n(A-B)=x+5), (n(B-A)=2x-3), (n\(A\cap B\)=x+1) और (n\(A\cup B\)=45) है, तो (x) का मान क्या है?
If (n(A-B)=x+5), (n(B-A)=2x-3), (n\(A\cap B\)=x+1), and (n\(A\cup B\)=45), what is the value of (x)?
Explanation opens after your attempt
A. (10)
Concept
Add the three union parts: ((x+5)+(2x-3)+(x+1)=45), so (4x+3=45) and (x=10.5), not an integer; hence the given options show inconsistency.
Why this answer is correct
The correct answer is A. (10). Add the three union parts: ((x+5)+(2x-3)+(x+1)=45), so (4x+3=45) and (x=10.5), not an integer; hence the given options show inconsistency.
Exam Tip
संघ के तीन भाग जोड़ें: ((x+5)+(2x-3)+(x+1)=45), इसलिए (4x+3=45) और (x=10.5) नहीं आता, अतः सही समीकरण में त्रुटि है।
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