यदि (n(A-B)=2x+3), (n(B-A)=x+7), (n\(A\cap B\)=x-1) और (n\(A\cup B\)=45) है, तो (x) कितना है?
If (n(A-B)=2x+3), (n(B-A)=x+7), (n\(A\cap B\)=x-1) and (n\(A\cup B\)=45), then what is (x)?
Explanation opens after your attempt
A. (9)
Concept
The union is (2x+3+x+7+x-1=4x+9=45), so (x=9). The sum of disjoint regions directly gives the union.
Why this answer is correct
The correct answer is A. (9). The union is (2x+3+x+7+x-1=4x+9=45), so (x=9). The sum of disjoint regions directly gives the union.
Exam Tip
संघ (2x+3+x+7+x-1=4x+9=45), इसलिए (x=9) है। अलग क्षेत्रों का योग सीधे संघ देता है।
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