यदि (n(A-B)=29) और (n(B-A)=17) है, तो (n\(A\triangle B\)) कितना होगा?
If (n(A-B)=29) and (n(B-A)=17), what is (n\(A\triangle B\))?
Explanation opens after your attempt
B. (46)
Concept
The symmetric difference includes only (A) and only (B), so (29+17=46). The common part is not included.
Why this answer is correct
The correct answer is B. (46). The symmetric difference includes only (A) and only (B), so (29+17=46). The common part is not included.
Exam Tip
सममित अंतर में केवल (A) और केवल (B) वाले भाग आते हैं, इसलिए (29+17=46)। साझा भाग इसमें शामिल नहीं होता।
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