यदि (n(A)=69), (n(B)=74), (n(A-B)=28) है, तो (n\(A\cup B\)) कितना है?

If (n(A)=69), (n(B)=74), (n(A-B)=28), then what is (n\(A\cup B\))?

Explanation opens after your attempt
Correct Answer

A. (102)

Step 1

Concept

(n\(A\cap B\)=69-28=41), so (n\(A\cup B\)=69+74-41=102). Find the common part first.

Step 2

Why this answer is correct

The correct answer is A. (102). (n\(A\cap B\)=69-28=41), so (n\(A\cup B\)=69+74-41=102). Find the common part first.

Step 3

Exam Tip

(n\(A\cap B\)=69-28=41), इसलिए (n\(A\cup B\)=69+74-41=102) है। पहले साझा भाग खोजें।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=69), (n(B)=74), (n(A-B)=28) है, तो (n\(A\cup B\)) कितना है? / If (n(A)=69), (n(B)=74), (n(A-B)=28), then what is (n\(A\cup B\))?

Correct Answer: A. (102). Explanation: (n\(A\cap B\)=69-28=41), इसलिए (n\(A\cup B\)=69+74-41=102) है। पहले साझा भाग खोजें। / (n\(A\cap B\)=69-28=41), so (n\(A\cup B\)=69+74-41=102). Find the common part first.

Which concept should I revise for this Mathematics MCQ?

(n\(A\cap B\)=69-28=41), so (n\(A\cup B\)=69+74-41=102). Find the common part first.

What exam hint can help solve this Mathematics question?

(n\(A\cap B\)=69-28=41), इसलिए (n\(A\cup B\)=69+74-41=102) है। पहले साझा भाग खोजें।