यदि (n(A)=52), (n(B)=47), (n\(A\cap B\)=21) और (n(U)=80), तो (n(\(A\cup B\)')) क्या है?
If (n(A)=52), (n(B)=47), (n\(A\cap B\)=21), and (n(U)=80), what is (n(\(A\cup B\)'))?
Explanation opens after your attempt
A. (2)
Concept
(n\(A\cup B\)=52+47-21=78). Therefore the number outside is (80-78=2).
Why this answer is correct
The correct answer is A. (2). (n\(A\cup B\)=52+47-21=78). Therefore the number outside is (80-78=2).
Exam Tip
(n\(A\cup B\)=52+47-21=78)। अतः बाहर के तत्व (80-78=2) हैं।
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