यदि \(f(x)=x+\frac{2}{x}\) और \(g(x)=x-\frac{2}{x}\) हैं, तो ((fg)(x)) किसके बराबर है?

If \(f(x)=x+\frac{2}{x}\) and \(g(x)=x-\frac{2}{x}\), what is ((fg)(x)) equal to?

Author: Muft Shiksha Editorial Team Published: Updated:
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Correct Answer

A. \(x^2-\frac{4}{x^2}\), \(x\ne 0\)

Explanation

Simple Explanation

\((fg)(x)=\left(x+\frac{2}{x}\right)\left(x-\frac{2}{x}\right)=x^2-\frac{4}{x^2}\)। पहचान \((a+b)(a-b)=a^2-b^2\) लगाएं। / \((fg)(x)=\left(x+\frac{2}{x}\right)\left(x-\frac{2}{x}\right)=x^2-\frac{4}{x^2}\). Apply \((a+b)(a-b)=a^2-b^2\).

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(f(x)=x+\frac{2}{x}\) और \(g(x)=x-\frac{2}{x}\) हैं, तो ((fg)(x)) किसके बराबर है? / If \(f(x)=x+\frac{2}{x}\) and \(g(x)=x-\frac{2}{x}\), what is ((fg)(x)) equal to?

Correct Answer: A. \(x^2-\frac{4}{x^2}\), \(x\ne 0\). Explanation: \((fg)(x)=\left(x+\frac{2}{x}\right)\left(x-\frac{2}{x}\right)=x^2-\frac{4}{x^2}\)। पहचान \((a+b)(a-b)=a^2-b^2\) लगाएं। / \((fg)(x)=\left(x+\frac{2}{x}\right)\left(x-\frac{2}{x}\right)=x^2-\frac{4}{x^2}\). Apply \((a+b)(a-b)=a^2-b^2\).