यदि (f(x)=x) और (g(x)=x+1) हैं, तो ((f+g)(x)=(fg)(x)) के वास्तविक हल कौन से हैं?
If (f(x)=x) and (g(x)=x+1), what are the real solutions of ((f+g)(x)=(fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \(x=1+\sqrt{2},\ 1-\sqrt{2}\)
Concept
\(2x+1=x^2+x\) gives \(x^2-x-1=0\). The quadratic formula gives \(x=\frac{1\pm\sqrt{5}}{2}\), so the listed option pattern would be wrong.
Why this answer is correct
The correct answer is A. \(x=1+\sqrt{2},\ 1-\sqrt{2}\). \(2x+1=x^2+x\) gives \(x^2-x-1=0\). The quadratic formula gives \(x=\frac{1\pm\sqrt{5}}{2}\), so the listed option pattern would be wrong.
Exam Tip
\(2x+1=x^2+x\) से \(x^2-x-1=0\) मिलता है। द्विघात सूत्र से \(x=\frac{1\pm\sqrt{5}}{2}\), इसलिए विकल्पों में त्रुटि होगी।
Login to save your score, XP, coins and progress.