यदि (f(x)=x-2) और (g(x)=|x|) हों, तो ((f-g)(x)) का मान (0) कब होगा?

If (f(x)=x-2) and (g(x)=|x|), when is ((f-g)(x)) equal to (0)?

Explanation opens after your attempt
Correct Answer

A. \(x\in{-1,0,1}\)

Step 1

Concept

In \(x^2=|x|\), put \(t=|x|\ge 0\), so \(t^2=t\). Thus (t=0) or (t=1), giving (x=-1,0,1).

Step 2

Why this answer is correct

The correct answer is A. \(x\in{-1,0,1}\). In \(x^2=|x|\), put \(t=|x|\ge 0\), so \(t^2=t\). Thus (t=0) or (t=1), giving (x=-1,0,1).

Step 3

Exam Tip

\(x^2=|x|\) में \(t=|x|\ge 0\) रखने पर \(t^2=t\), इसलिए (t=0) या (t=1)। अतः (x=-1,0,1) हैं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2) और (g(x)=|x|) हों, तो ((f-g)(x)) का मान (0) कब होगा? / If (f(x)=x-2) and (g(x)=|x|), when is ((f-g)(x)) equal to (0)?

Correct Answer: A. \(x\in{-1,0,1}\). Explanation: \(x^2=|x|\) में \(t=|x|\ge 0\) रखने पर \(t^2=t\), इसलिए (t=0) या (t=1)। अतः (x=-1,0,1) हैं। / In \(x^2=|x|\), put \(t=|x|\ge 0\), so \(t^2=t\). Thus (t=0) or (t=1), giving (x=-1,0,1).

Which concept should I revise for this Mathematics MCQ?

In \(x^2=|x|\), put \(t=|x|\ge 0\), so \(t^2=t\). Thus (t=0) or (t=1), giving (x=-1,0,1).

What exam hint can help solve this Mathematics question?

\(x^2=|x|\) में \(t=|x|\ge 0\) रखने पर \(t^2=t\), इसलिए (t=0) या (t=1)। अतः (x=-1,0,1) हैं।