यदि (f(x)=x-2) और (g(x)=|x|) हैं, तो (f-g) का न्यूनतम मान क्या है?
If (f(x)=x-2) and (g(x)=|x|), what is the minimum value of (f-g)?
Explanation opens after your attempt
Correct Answer
A. \(-\frac{1}{4}\)
Concept
The expression is \(x^2-|x|\). Put \(t=|x|\ge0\), then \(t^2-t\) has minimum \(-\frac{1}{4}\). For hard modulus questions, using (t) is helpful.
Why this answer is correct
The correct answer is A. \(-\frac{1}{4}\). The expression is \(x^2-|x|\). Put \(t=|x|\ge0\), then \(t^2-t\) has minimum \(-\frac{1}{4}\). For hard modulus questions, using (t) is helpful.
Exam Tip
मान \(x^2-|x|\) है, \(t=|x|\ge0\) रखने पर \(t^2-t\) का न्यूनतम \(-\frac{1}{4}\) है। कठिन प्रश्नों में मापांक को (t) से बदलना उपयोगी है।
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