यदि (f(x)=x-2-6x+9), (g(x)=x-3) और \(x\ne 3\), तो (\left\(\frac{f}{g}\right\)(x)) क्या है?
If (f(x)=x-2-6x+9), (g(x)=x-3), and \(x\ne 3\), what is (\left\(\frac{f}{g}\right\)(x))?
Explanation opens after your attempt
A. (x-3)
Concept
(f=(x-3)2), so \(\frac{f}{g}=x-3\) when \(x\ne 3\). Write the restriction while cancelling.
Why this answer is correct
The correct answer is A. (x-3). (f=(x-3)2), so \(\frac{f}{g}=x-3\) when \(x\ne 3\). Write the restriction while cancelling.
Exam Tip
(f=(x-3)2), इसलिए \(\frac{f}{g}=x-3\) जब \(x\ne 3\)। कटौती करते समय प्रतिबंध साथ लिखें।
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