यदि (f(x)=x-2-6x+9), (g(x)=x-3) और \(x\ne 3\), तो (\left\(\frac{f}{g}\right\)(x)) क्या है?

If (f(x)=x-2-6x+9), (g(x)=x-3), and \(x\ne 3\), what is (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. (x-3)

Step 1

Concept

(f=(x-3)2), so \(\frac{f}{g}=x-3\) when \(x\ne 3\). Write the restriction while cancelling.

Step 2

Why this answer is correct

The correct answer is A. (x-3). (f=(x-3)2), so \(\frac{f}{g}=x-3\) when \(x\ne 3\). Write the restriction while cancelling.

Step 3

Exam Tip

(f=(x-3)2), इसलिए \(\frac{f}{g}=x-3\) जब \(x\ne 3\)। कटौती करते समय प्रतिबंध साथ लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-6x+9), (g(x)=x-3) और \(x\ne 3\), तो (\left\(\frac{f}{g}\right\)(x)) क्या है? / If (f(x)=x-2-6x+9), (g(x)=x-3), and \(x\ne 3\), what is (\left\(\frac{f}{g}\right\)(x))?

Correct Answer: A. (x-3). Explanation: (f=(x-3)2), इसलिए \(\frac{f}{g}=x-3\) जब \(x\ne 3\)। कटौती करते समय प्रतिबंध साथ लिखें। / (f=(x-3)2), so \(\frac{f}{g}=x-3\) when \(x\ne 3\). Write the restriction while cancelling.

Which concept should I revise for this Mathematics MCQ?

(f=(x-3)2), so \(\frac{f}{g}=x-3\) when \(x\ne 3\). Write the restriction while cancelling.

What exam hint can help solve this Mathematics question?

(f=(x-3)2), इसलिए \(\frac{f}{g}=x-3\) जब \(x\ne 3\)। कटौती करते समय प्रतिबंध साथ लिखें।