यदि (f(x)=x-2+3x+2) और (g(x)=x+1) हों, तो \(x\ne -1\) के लिए (\left\(\frac{f}{g}\right\)(x)) क्या है?

If (f(x)=x-2+3x+2) and (g(x)=x+1), what is (\left\(\frac{f}{g}\right\)(x)) for \(x\ne -1\)?

Explanation opens after your attempt
Correct Answer

A. (x+2)

Step 1

Concept

(x-2+3x+2=(x+1)(x+2)), so the quotient is (x+2). Exclude the zero of the denominator first.

Step 2

Why this answer is correct

The correct answer is A. (x+2). (x-2+3x+2=(x+1)(x+2)), so the quotient is (x+2). Exclude the zero of the denominator first.

Step 3

Exam Tip

(x-2+3x+2=(x+1)(x+2)), इसलिए भागफल (x+2) है। हर का शून्य मान पहले हटाएं।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2+3x+2) और (g(x)=x+1) हों, तो \(x\ne -1\) के लिए (\left\(\frac{f}{g}\right\)(x)) क्या है? / If (f(x)=x-2+3x+2) and (g(x)=x+1), what is (\left\(\frac{f}{g}\right\)(x)) for \(x\ne -1\)?

Correct Answer: A. (x+2). Explanation: (x-2+3x+2=(x+1)(x+2)), इसलिए भागफल (x+2) है। हर का शून्य मान पहले हटाएं। / (x-2+3x+2=(x+1)(x+2)), so the quotient is (x+2). Exclude the zero of the denominator first.

Which concept should I revise for this Mathematics MCQ?

(x-2+3x+2=(x+1)(x+2)), so the quotient is (x+2). Exclude the zero of the denominator first.

What exam hint can help solve this Mathematics question?

(x-2+3x+2=(x+1)(x+2)), इसलिए भागफल (x+2) है। हर का शून्य मान पहले हटाएं।