यदि (f(x)=x-2+2x+2) और (g(x)=x+1) हैं, तो ((f-g)(x)) का न्यूनतम मान क्या होगा?
If (f(x)=x-2+2x+2) and (g(x)=x+1), what is the minimum value of ((f-g)(x))?
Explanation opens after your attempt
A. \(\frac{3}{4}\)
Concept
((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4}). Therefore the minimum is \(\frac{3}{4}\).
Why this answer is correct
The correct answer is A. \(\frac{3}{4}\). ((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4}). Therefore the minimum is \(\frac{3}{4}\).
Exam Tip
((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4})। इसलिए न्यूनतम \(\frac{3}{4}\) है।
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