यदि (f(x)=x-2-1) और (g(x)=x-2+1) हैं, तो (\left\(\frac{f}{g}\right\)(x)<1) किसके लिए सत्य है?
If (f(x)=x-2-1) and (g(x)=x-2+1), for which (x) is (\left\(\frac{f}{g}\right\)(x)<1) true?
Explanation opens after your attempt
Correct Answer
A. सभी \(x\in\mathbb{R}\)all \(x\in\mathbb{R}\)
Concept
Since \(x^2+1>0\) and \(x^2-1<x^2+1\), the ratio is always less than (1). With a positive denominator, the inequality direction does not change.
Why this answer is correct
The correct answer is A. सभी \(x\in\mathbb{R}\) / all \(x\in\mathbb{R}\). Since \(x^2+1>0\) and \(x^2-1<x^2+1\), the ratio is always less than (1). With a positive denominator, the inequality direction does not change.
Exam Tip
क्योंकि \(x^2+1>0\) और \(x^2-1<x^2+1\), अनुपात हमेशा (1) से छोटा है। धन हर होने पर असमता की दिशा नहीं बदलती।
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