यदि (f(x)=x-1) और (g(x)=x+1) हों, तो (\left\(\frac{f}{g}\right\)(x)) का डोमेन क्या है?

If (f(x)=x-1) and (g(x)=x+1), what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-1}\)

Step 1

Concept

In division, (g(x)\ne 0), so \(x+1\ne 0\) and \(x\ne -1\). The numerator may be zero.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-1}\). In division, (g(x)\ne 0), so \(x+1\ne 0\) and \(x\ne -1\). The numerator may be zero.

Step 3

Exam Tip

भाग में (g(x)\ne 0) चाहिए, इसलिए \(x+1\ne 0\) और \(x\ne -1\)। अंश शून्य हो सकता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-1) और (g(x)=x+1) हों, तो (\left\(\frac{f}{g}\right\)(x)) का डोमेन क्या है? / If (f(x)=x-1) and (g(x)=x+1), what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Correct Answer: A. \(\mathbb{R}-{-1}\). Explanation: भाग में (g(x)\ne 0) चाहिए, इसलिए \(x+1\ne 0\) और \(x\ne -1\)। अंश शून्य हो सकता है। / In division, (g(x)\ne 0), so \(x+1\ne 0\) and \(x\ne -1\). The numerator may be zero.

Which concept should I revise for this Mathematics MCQ?

In division, (g(x)\ne 0), so \(x+1\ne 0\) and \(x\ne -1\). The numerator may be zero.

What exam hint can help solve this Mathematics question?

भाग में (g(x)\ne 0) चाहिए, इसलिए \(x+1\ne 0\) और \(x\ne -1\)। अंश शून्य हो सकता है।