यदि (f(x)=x+1) और (g(x)=\frac{1}{x+1}) हों, तो ((fg)(x)) का सही कथन कौन-सा है?

If (f(x)=x+1) and (g(x)=\frac{1}{x+1}), which statement about ((fg)(x)) is correct?

Explanation opens after your attempt
Correct Answer

A. ((fg)(x)=1), \(x\ne -1\)

Step 1

Concept

The product is (1), but \(x\ne -1\) because of the denominator of (g(x)). It is important to write the domain with the simplified form.

Step 2

Why this answer is correct

The correct answer is A. ((fg)(x)=1), \(x\ne -1\). The product is (1), but \(x\ne -1\) because of the denominator of (g(x)). It is important to write the domain with the simplified form.

Step 3

Exam Tip

गुणनफल (1) है, पर (g(x)) के हर के कारण \(x\ne -1\)। सरल रूप के साथ डोमेन लिखना जरूरी है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x+1) और (g(x)=\frac{1}{x+1}) हों, तो ((fg)(x)) का सही कथन कौन-सा है? / If (f(x)=x+1) and (g(x)=\frac{1}{x+1}), which statement about ((fg)(x)) is correct?

Correct Answer: A. ((fg)(x)=1), \(x\ne -1\). Explanation: गुणनफल (1) है, पर (g(x)) के हर के कारण \(x\ne -1\)। सरल रूप के साथ डोमेन लिखना जरूरी है। / The product is (1), but \(x\ne -1\) because of the denominator of (g(x)). It is important to write the domain with the simplified form.

Which concept should I revise for this Mathematics MCQ?

The product is (1), but \(x\ne -1\) because of the denominator of (g(x)). It is important to write the domain with the simplified form.

What exam hint can help solve this Mathematics question?

गुणनफल (1) है, पर (g(x)) के हर के कारण \(x\ne -1\)। सरल रूप के साथ डोमेन लिखना जरूरी है।