यदि (f(x)=\sqrt{x}) और (g(x)=\sqrt{1-x}) हों, तो ((f+g)(x)) का प्रांत क्या है?

If (f(x)=\sqrt{x}) and (g(x)=\sqrt{1-x}), what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. ( [0,1] )

Step 1

Concept

The first root gives \(x\ge 0\), and the second gives \(x\le 1\). Their intersection is ( [0,1] ).

Step 2

Why this answer is correct

The correct answer is A. ( [0,1] ). The first root gives \(x\ge 0\), and the second gives \(x\le 1\). Their intersection is ( [0,1] ).

Step 3

Exam Tip

पहले मूल से \(x\ge 0\) और दूसरे से \(x\le 1\) मिलता है। दोनों शर्तों का प्रतिच्छेद ( [0,1] ) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x}) और (g(x)=\sqrt{1-x}) हों, तो ((f+g)(x)) का प्रांत क्या है? / If (f(x)=\sqrt{x}) and (g(x)=\sqrt{1-x}), what is the domain of ((f+g)(x))?

Correct Answer: A. ( [0,1] ). Explanation: पहले मूल से \(x\ge 0\) और दूसरे से \(x\le 1\) मिलता है। दोनों शर्तों का प्रतिच्छेद ( [0,1] ) है। / The first root gives \(x\ge 0\), and the second gives \(x\le 1\). Their intersection is ( [0,1] ).

Which concept should I revise for this Mathematics MCQ?

The first root gives \(x\ge 0\), and the second gives \(x\le 1\). Their intersection is ( [0,1] ).

What exam hint can help solve this Mathematics question?

पहले मूल से \(x\ge 0\) और दूसरे से \(x\le 1\) मिलता है। दोनों शर्तों का प्रतिच्छेद ( [0,1] ) है।