यदि (f(x)=\sqrt{x}) और (g(x)=\frac{1}{x-4}) हों, तो ((fg)(x)) का डोमेन क्या है?

If (f(x)=\sqrt{x}) and (g(x)=\frac{1}{x-4}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \([0,\infty\)-{4})

Step 1

Concept

\(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x\ne 4\). Take the intersection of both conditions.

Step 2

Why this answer is correct

The correct answer is A. \([0,\infty\)-{4}). \(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x\ne 4\). Take the intersection of both conditions.

Step 3

Exam Tip

\(\sqrt{x}\) के लिए \(x\ge 0\) और हर के लिए \(x\ne 4\) चाहिए। दोनों शर्तों का प्रतिच्छेद लें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x}) और (g(x)=\frac{1}{x-4}) हों, तो ((fg)(x)) का डोमेन क्या है? / If (f(x)=\sqrt{x}) and (g(x)=\frac{1}{x-4}), what is the domain of ((fg)(x))?

Correct Answer: A. \([0,\infty\)-{4}). Explanation: \(\sqrt{x}\) के लिए \(x\ge 0\) और हर के लिए \(x\ne 4\) चाहिए। दोनों शर्तों का प्रतिच्छेद लें। / \(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x\ne 4\). Take the intersection of both conditions.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{x}\) needs \(x\ge 0\), and the denominator needs \(x\ne 4\). Take the intersection of both conditions.

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) के लिए \(x\ge 0\) और हर के लिए \(x\ne 4\) चाहिए। दोनों शर्तों का प्रतिच्छेद लें।