यदि (f(x)=\sqrt{x-2-16}) है, तो (f(-5)) क्या है?

If (f(x)=\sqrt{x-2-16}), what is (f(-5))?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

(f(-5)=\sqrt{25-16}=\sqrt{9}=3). In exams the principal value of square root is non-negative.

Step 2

Why this answer is correct

The correct answer is A. (3). (f(-5)=\sqrt{25-16}=\sqrt{9}=3). In exams the principal value of square root is non-negative.

Step 3

Exam Tip

(f(-5)=\sqrt{25-16}=\sqrt{9}=3) है। परीक्षा में वर्गमूल की principal value non-negative होती है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x-2-16}) है, तो (f(-5)) क्या है? / If (f(x)=\sqrt{x-2-16}), what is (f(-5))?

Correct Answer: A. (3). Explanation: (f(-5)=\sqrt{25-16}=\sqrt{9}=3) है। परीक्षा में वर्गमूल की principal value non-negative होती है। / (f(-5)=\sqrt{25-16}=\sqrt{9}=3). In exams the principal value of square root is non-negative.

Which concept should I revise for this Mathematics MCQ?

(f(-5)=\sqrt{25-16}=\sqrt{9}=3). In exams the principal value of square root is non-negative.

What exam hint can help solve this Mathematics question?

(f(-5)=\sqrt{25-16}=\sqrt{9}=3) है। परीक्षा में वर्गमूल की principal value non-negative होती है।