यदि (f(x)=\sqrt{x-1}) और (g(x)=\sqrt{3-x}) हैं, तो ((f-g)(x)) का प्रांत कौन सा है?

If (f(x)=\sqrt{x-1}) and (g(x)=\sqrt{3-x}), what is the domain of ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(1\le x\le3\)

Step 1

Concept

Both square roots must be defined, so \(x-1\ge0\) and \(3-x\ge0\). Hence \(1\le x\le3\).

Step 2

Why this answer is correct

The correct answer is A. \(1\le x\le3\). Both square roots must be defined, so \(x-1\ge0\) and \(3-x\ge0\). Hence \(1\le x\le3\).

Step 3

Exam Tip

दोनों वर्गमूल परिभाषित होने चाहिए, इसलिए \(x-1\ge0\) और \(3-x\ge0\)। अतः \(1\le x\le3\)।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x-1}) और (g(x)=\sqrt{3-x}) हैं, तो ((f-g)(x)) का प्रांत कौन सा है? / If (f(x)=\sqrt{x-1}) and (g(x)=\sqrt{3-x}), what is the domain of ((f-g)(x))?

Correct Answer: A. \(1\le x\le3\). Explanation: दोनों वर्गमूल परिभाषित होने चाहिए, इसलिए \(x-1\ge0\) और \(3-x\ge0\)। अतः \(1\le x\le3\)। / Both square roots must be defined, so \(x-1\ge0\) and \(3-x\ge0\). Hence \(1\le x\le3\).

Which concept should I revise for this Mathematics MCQ?

Both square roots must be defined, so \(x-1\ge0\) and \(3-x\ge0\). Hence \(1\le x\le3\).

What exam hint can help solve this Mathematics question?

दोनों वर्गमूल परिभाषित होने चाहिए, इसलिए \(x-1\ge0\) और \(3-x\ge0\)। अतः \(1\le x\le3\)।