यदि (f(x)=\sqrt{4-x}) और (g(x)=\frac{1}{x}) हों, तो ((f+g)(x)) का डोमेन क्या है?

If (f(x)=\sqrt{4-x}) and (g(x)=\frac{1}{x}), what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,4]-{0}\)

Step 1

Concept

The square root needs \(4-x\ge 0\), i.e. \(x\le 4\), and the denominator needs \(x\ne 0\). Take both conditions together.

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,4]-{0}\). The square root needs \(4-x\ge 0\), i.e. \(x\le 4\), and the denominator needs \(x\ne 0\). Take both conditions together.

Step 3

Exam Tip

वर्गमूल के लिए \(4-x\ge 0\), यानी \(x\le 4\), और हर के लिए \(x\ne 0\)। दोनों शर्तें साथ लें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{4-x}) और (g(x)=\frac{1}{x}) हों, तो ((f+g)(x)) का डोमेन क्या है? / If (f(x)=\sqrt{4-x}) and (g(x)=\frac{1}{x}), what is the domain of ((f+g)(x))?

Correct Answer: A. (\(-\infty,4]-{0}\). Explanation: वर्गमूल के लिए \(4-x\ge 0\), यानी \(x\le 4\), और हर के लिए \(x\ne 0\)। दोनों शर्तें साथ लें। / The square root needs \(4-x\ge 0\), i.e. \(x\le 4\), and the denominator needs \(x\ne 0\). Take both conditions together.

Which concept should I revise for this Mathematics MCQ?

The square root needs \(4-x\ge 0\), i.e. \(x\le 4\), and the denominator needs \(x\ne 0\). Take both conditions together.

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(4-x\ge 0\), यानी \(x\le 4\), और हर के लिए \(x\ne 0\)। दोनों शर्तें साथ लें।