यदि (f(x)=\frac{x}{x+2}) और (g(x)=\frac{2}{x+2}) हैं, तो ((f+g)(x)) का सरल रूप क्या है?

If (f(x)=\frac{x}{x+2}) and (g(x)=\frac{2}{x+2}), what is the simplified form of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. (1), \(x \neq -2\)

Step 1

Concept

((f+g)(x)=\frac{x+2}{x+2}=1), but \(x+2 \neq 0\). It is important to write the domain restriction with the simplified answer.

Step 2

Why this answer is correct

The correct answer is A. (1), \(x \neq -2\). ((f+g)(x)=\frac{x+2}{x+2}=1), but \(x+2 \neq 0\). It is important to write the domain restriction with the simplified answer.

Step 3

Exam Tip

((f+g)(x)=\frac{x+2}{x+2}=1), लेकिन \(x+2 \neq 0\)। सरल उत्तर के साथ प्रांत का प्रतिबंध लिखना जरूरी है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x}{x+2}) और (g(x)=\frac{2}{x+2}) हैं, तो ((f+g)(x)) का सरल रूप क्या है? / If (f(x)=\frac{x}{x+2}) and (g(x)=\frac{2}{x+2}), what is the simplified form of ((f+g)(x))?

Correct Answer: A. (1), \(x \neq -2\). Explanation: ((f+g)(x)=\frac{x+2}{x+2}=1), लेकिन \(x+2 \neq 0\)। सरल उत्तर के साथ प्रांत का प्रतिबंध लिखना जरूरी है। / ((f+g)(x)=\frac{x+2}{x+2}=1), but \(x+2 \neq 0\). It is important to write the domain restriction with the simplified answer.

Which concept should I revise for this Mathematics MCQ?

((f+g)(x)=\frac{x+2}{x+2}=1), but \(x+2 \neq 0\). It is important to write the domain restriction with the simplified answer.

What exam hint can help solve this Mathematics question?

((f+g)(x)=\frac{x+2}{x+2}=1), लेकिन \(x+2 \neq 0\)। सरल उत्तर के साथ प्रांत का प्रतिबंध लिखना जरूरी है।