यदि (f(x)=\frac{x+2}{x-2}) और (g(x)=\frac{x-2}{x+2}) हों, तो ((f+g)(x)) का सरल रूप क्या है?
If (f(x)=\frac{x+2}{x-2}) and (g(x)=\frac{x-2}{x+2}), what is the simplified form of ((f+g)(x))?
Explanation opens after your attempt
A. \(\frac{2x^2+8}{x^2-4},\ x\ne \pm2\)
Concept
The numerator is ((x+2)2+(x-2)2=2x-2+8). Expand both squares carefully while taking a common denominator.
Why this answer is correct
The correct answer is A. \(\frac{2x^2+8}{x^2-4},\ x\ne \pm2\). The numerator is ((x+2)2+(x-2)2=2x-2+8). Expand both squares carefully while taking a common denominator.
Exam Tip
अंश ((x+2)2+(x-2)2=2x-2+8) है। समान हर बनाते समय पूरे वर्ग ध्यान से खोलें।
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