यदि (f(x)=\frac{x+2}{x-2}) और (g(x)=\frac{x-2}{x+2}) हैं, तो ((f+g)(x)) का सही रूप क्या है?
If (f(x)=\frac{x+2}{x-2}) and (g(x)=\frac{x-2}{x+2}), what is the correct form of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\frac{2x^2+8}{x^2-4},\ x\ne\pm2\)
Concept
((x+2)2+(x-2)2=2x-2+8) and the denominator is \(x^2-4\). The middle terms cancel when expanding the squares.
Why this answer is correct
The correct answer is A. \(\frac{2x^2+8}{x^2-4},\ x\ne\pm2\). ((x+2)2+(x-2)2=2x-2+8) and the denominator is \(x^2-4\). The middle terms cancel when expanding the squares.
Exam Tip
((x+2)2+(x-2)2=2x-2+8) और हर \(x^2-4\) है। वर्गों को फैलाते समय मध्यम पद कटते हैं।
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