यदि (f(x)=\frac{x-2}{x+1}) और (g(x)=\frac{x+3}{x+1}) हैं, तो ((f-g)(x)) क्या होगा?
If (f(x)=\frac{x-2}{x+1}) and (g(x)=\frac{x+3}{x+1}), what is ((f-g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\frac{-5}{x+1}, x \neq -1\)
Concept
With the same denominator, subtract numerators: (\frac{x-2-(x+3)}{x+1}=\frac{-5}{x+1}). Because of denominator (x+1), \(x \neq -1\).
Why this answer is correct
The correct answer is A. \(\frac{-5}{x+1}, x \neq -1\). With the same denominator, subtract numerators: (\frac{x-2-(x+3)}{x+1}=\frac{-5}{x+1}). Because of denominator (x+1), \(x \neq -1\).
Exam Tip
समान हर होने पर अंश घटाएँ: (\frac{x-2-(x+3)}{x+1}=\frac{-5}{x+1})। हर (x+1) के कारण \(x \neq -1\)।
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