यदि (f(x)=\frac{x+1}{x-2}) और (g(x)=x-2-4) हों, तो ((fg)(x)) का डोमेन क्या है?
If (f(x)=\frac{x+1}{x-2}) and (g(x)=x-2-4), what is the domain of ((fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{2}\)
Concept
(g(x)) is defined for all real (x), but (f(x)) needs \(x-2\ne 0\). For product also, take the common domain.
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{2}\). (g(x)) is defined for all real (x), but (f(x)) needs \(x-2\ne 0\). For product also, take the common domain.
Exam Tip
(g(x)) सभी वास्तविक (x) पर परिभाषित है, पर (f(x)) में \(x-2\ne 0\) चाहिए। गुणन में भी साझा डोमेन लेते हैं।
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