यदि (f(x)=\frac{x+1}{x-1}) और (g(x)=x-1) हैं, तो ((fg)(x)) का प्रांत क्या है?
If (f(x)=\frac{x+1}{x-1}) and (g(x)=x-1), what is the domain of ((fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \(x \in \mathbb{R}, x \neq 1\)
Concept
In the original (f(x)), \(x-1 \neq 0\), so \(x \neq 1\), even if simplification occurs after multiplication. Decide the domain from original expressions.
Why this answer is correct
The correct answer is A. \(x \in \mathbb{R}, x \neq 1\). In the original (f(x)), \(x-1 \neq 0\), so \(x \neq 1\), even if simplification occurs after multiplication. Decide the domain from original expressions.
Exam Tip
मूल (f(x)) में \(x-1 \neq 0\), इसलिए \(x \neq 1\), भले ही गुणा के बाद सरलीकरण हो। प्रांत मूल अभिव्यक्तियों से तय करें।
Login to save your score, XP, coins and progress.