यदि (f(x)=\frac{x+1}{x-1}) और (g(x)=\frac{x-1}{x+1}) हों, तो ((fg)(x)) का सही प्रांत क्या होगा?
If (f(x)=\frac{x+1}{x-1}) and (g(x)=\frac{x-1}{x+1}), what is the correct domain of ((fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \( \mathbb{R}\setminus{-1,1} \)
Concept
The denominators require \(x\ne 1\) and \(x\ne -1\). The product becomes (1), but the restrictions remain.
Why this answer is correct
The correct answer is A. \( \mathbb{R}\setminus{-1,1} \). The denominators require \(x\ne 1\) and \(x\ne -1\). The product becomes (1), but the restrictions remain.
Exam Tip
दोनों हरों के कारण \(x\ne 1\) और \(x\ne -1\) चाहिए। गुणन (1) बनता है पर प्रतिबंध बने रहते हैं।
Login to save your score, XP, coins and progress.