यदि (f(x)=\frac{2x}{x-2-4}) और (g(x)=\frac{1}{x-2}) हैं, तो ((f-g)(x)) का सरल रूप क्या है?

If (f(x)=\frac{2x}{x-2-4}) and (g(x)=\frac{1}{x-2}), what is the simplified form of ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. (\frac{2}{(x-2)(x+2)})

Step 1

Concept

With common denominator ((x-2)(x+2)), numerator is (2x-(x+2)=x-2), so the form is \(\frac{1}{x+2}\) with \(x\ne\pm2\). Thus option (C) is the simplification.

Step 2

Why this answer is correct

The correct answer is A. (\frac{2}{(x-2)(x+2)}). With common denominator ((x-2)(x+2)), numerator is (2x-(x+2)=x-2), so the form is \(\frac{1}{x+2}\) with \(x\ne\pm2\). Thus option (C) is the simplification.

Step 3

Exam Tip

समान हर ((x-2)(x+2)) लेने पर अंश (2x-(x+2)=x-2) होगा, इसलिए \(\frac{1}{x+2}\) पर \(x\ne\pm2\)। सही सरलीकरण विकल्प (C) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{2x}{x-2-4}) और (g(x)=\frac{1}{x-2}) हैं, तो ((f-g)(x)) का सरल रूप क्या है? / If (f(x)=\frac{2x}{x-2-4}) and (g(x)=\frac{1}{x-2}), what is the simplified form of ((f-g)(x))?

Correct Answer: A. (\frac{2}{(x-2)(x+2)}). Explanation: समान हर ((x-2)(x+2)) लेने पर अंश (2x-(x+2)=x-2) होगा, इसलिए \(\frac{1}{x+2}\) पर \(x\ne\pm2\)। सही सरलीकरण विकल्प (C) है। / With common denominator ((x-2)(x+2)), numerator is (2x-(x+2)=x-2), so the form is \(\frac{1}{x+2}\) with \(x\ne\pm2\). Thus option (C) is the simplification.

Which concept should I revise for this Mathematics MCQ?

With common denominator ((x-2)(x+2)), numerator is (2x-(x+2)=x-2), so the form is \(\frac{1}{x+2}\) with \(x\ne\pm2\). Thus option (C) is the simplification.

What exam hint can help solve this Mathematics question?

समान हर ((x-2)(x+2)) लेने पर अंश (2x-(x+2)=x-2) होगा, इसलिए \(\frac{1}{x+2}\) पर \(x\ne\pm2\)। सही सरलीकरण विकल्प (C) है।